A) \[2\]
B) \[4\]
C) \[4/3\]
D) \[3/4\]
Correct Answer: C
Solution :
\[2{{\cot }^{2}}\left( \frac{\pi }{6} \right)+4\,{{\tan }^{2}}\left( \frac{\pi }{6} \right)-3\text{cosec}\frac{\pi }{6}\] \[=2{{(\sqrt{3})}^{2}}+4{{\left( \frac{1}{\sqrt{3}} \right)}^{2}}-3(2)=2\times 3+\frac{4}{3}-6=\frac{4}{3}\]You need to login to perform this action.
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