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J & K CET Engineering J and K - CET Engineering Solved Paper-2014

  • question_answer
    The neutral point on potentiometer's scale for two cells of EMF \[2.1\] and E volts is observed at distances  \[40\text{ }cm\]and  \[56\text{ }cm\]respectively. The value of E is

    A)  \[2.10\,\,V\]             

    B)  \[2.94\,\,V\]

    C)  \[1.50\,\,V\]             

    D)  \[~1.20\,\,V\]

    Correct Answer: B

    Solution :

    For equating emf of two ceils \[\frac{{{e}_{1}}}{{{e}_{2}}}=\frac{{{I}_{1}}}{{{I}_{2}}}\] \[\frac{2.1}{E}=\frac{40}{56}\] \[E=\frac{2.1\times 56}{40}=2.94\,V\]


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