A) \[0.50\]and \[1020\text{ }kHz\]
B) \[0.66\]and \[1020\text{ }kHz\]
C) \[0.50\]and \[980\text{ }kHz\]
D) \[0.66\]and \[980\text{ }kHz\]
Correct Answer: A
Solution :
Modulation index \[(\mu )=\frac{{{A}_{m}}}{{{A}_{C}}}\] \[=\frac{15}{30}=\frac{1}{2}\] Frequency of upper side band \[=({{f}_{c}}+{{f}_{m}})\] \[=1000+20=1020kHz\]You need to login to perform this action.
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