A) \[NO_{3}^{-}<O{{H}^{-}}<pyridine<PP{{h}_{3}}\]
B) \[O{{H}^{-}}<NO_{3}^{-}<PP{{h}_{3}}<\text{pyridine}\]
C) \[O{{H}^{-}}<NO_{3}^{-}<\text{pyridine}<PP{{h}_{3}}\]
D) \[NO_{3}^{-}<O{{H}^{-}}<PP{{h}_{3}}<Pyridine\]
Correct Answer: A
Solution :
Increasing order of crystal field splitting power is as follows: \[\underset{\text{weak}\,\text{field}\,\text{ligand}}{\mathop{NO_{3}^{-}<O{{H}^{-}}}}\,\underset{\text{strong}\,\text{field}\,\text{ligand}}{\mathop{<pyridine<PP{{h}_{3}}}}\,\]You need to login to perform this action.
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