A) \[mg\,\,\cos \,\theta \]
B) \[mmg\,\,\cos \,\theta \]
C) \[mg\,\,sin\,\theta \]
D) \[mmg\,\,sin\,\theta \]
Correct Answer: C
Solution :
Suppose a force F is acting on the block as shown in the figure. Minimum value of the force required to just move the block up is - \[{{F}_{\min }}=mg\,\sin \,\theta +{{f}_{\min }}\] Where, f = frictional force \[{{f}_{\min }}=0\] \[\Rightarrow \] \[{{F}_{\min }}=mg\,\sin \,\theta \]You need to login to perform this action.
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