A) only less than \[{{45}^{o}}\]
B) only greater than \[{{45}^{o}}\]
C) any value in the range \[{{0}^{o}}\] to \[{{90}^{o}}\] except \[{{45}^{o}}\]
D) any value in the range \[{{0}^{o}}\] to \[{{90}^{o}}\] including \[{{45}^{o}}\]
Correct Answer: C
Solution :
Brewster's angle corresponding to two media of refractive indices \[{{r}_{1}}\] and \[{{r}_{2}}\] is \[\tan \,\,{{i}_{B}}=\left( \frac{{{n}_{2}}}{{{n}_{1}}} \right)\] Where, \[{{n}_{2}}\] is refractive index of denser medium and \[{{n}_{1}}\] is refractive index of rarer medium. If two mediums are same, i.e. \[{{n}_{1}}={{n}_{2}}\Rightarrow \tan \,\,{{i}_{B}}=1\] or \[{{i}_{B}}={{45}^{o}}\] Polarisation is not possible if two mediums are same. Therefore \[{{i}_{B}}\ne {{45}^{o}}\] Hence, Brewster's angle can have any value in the range \[{{0}^{o}}\] to \[{{90}^{o}}\] except \[{{45}^{o}}\].You need to login to perform this action.
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