A) \[PA=PB\]
B) \[{{t}_{A}}<{{t}_{B}}\]
C) \[{{v}_{A}}<{{v}_{B}}\]
D) Ball A hits the ground at an angle \[(-\theta )\] with horizontal
Correct Answer: C
Solution :
Consider, the two projectiles projected from \[O\]and P as shown in the figure. Range of both the particles \[R=\frac{{{v}^{2}}\,\,\sin \,2\theta }{g}\] \[\Rightarrow \] \[OA'=PB=R\] Clearly, velocity at the points A' and B will be same. Velocity of the ball following the trajectory OC? A?. Will increase after A' due to accelerated motion under gravity. Therefore, we can say that \[{{v}_{A}}>{{v}_{B}}\]You need to login to perform this action.
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