A) \[\frac{f}{2}\]
B) \[\frac{3f}{4}\]
C) \[f\]
D) \[2f\]
Correct Answer: C
Solution :
When length of open tube is\[l,\]then fundamental frequency \[n=\frac{v}{\lambda }=\frac{v}{2l}\] When dipped in water, \[n=\frac{v}{\lambda }\] Given, \[\frac{l}{2}=\frac{\lambda }{4}\] \[\therefore \] \[n=\frac{v}{2l}=n\] Given, \[n=f\] \[\therefore \] \[n=f\]You need to login to perform this action.
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