A) 30 cal
B) 50 cal
C) 370 cal
D) 90 cal
Correct Answer: B
Solution :
The heat required to raise the temperature of gas, at constant volume\[({{C}_{V}})\]is \[{{Q}_{V}}={{C}_{V}}\Delta T\] ...(i) and at constant pressure is \[{{Q}_{P}}={{C}_{P}}\Delta T\] ...(ii) Also, \[\gamma =\frac{{{C}_{P}}}{{{C}_{V}}}\] ...(iii) From Eqs. (i), (ii) and (iii), we get \[\frac{{{Q}_{V}}}{{{Q}_{P}}}=\frac{{{C}_{P}}}{{{C}_{V}}}=\frac{1}{\gamma }\] For a diatomic gas \[\gamma =\frac{7}{5}\] \[\therefore \] \[{{Q}_{V}}=\frac{5}{7}\times 70=50\,cal\]You need to login to perform this action.
You will be redirected in
3 sec