A) 4.0 g of sulphur
B) 7.0 g of nitrogen
C) 0.5 g of hydrogen
D) 2.3 got sodium
Correct Answer: A
Solution :
Number of atoms in 1 g of an element \[=\frac{6.023\times {{10}^{23}}}{atomic\text{ }mass}\] \[\therefore \]Number of atoms in 2 g of oxygen \[=\frac{6.023\times {{10}^{23}}\times 2}{16}\] \[=\frac{6.023\times {{10}^{23}}}{8}\] and number of atoms in 4 g of sulphur \[=\frac{6.023\times {{10}^{23}}\times 4}{32}\] \[=\frac{6.023\times {{10}^{23}}}{8}\]
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