A) its velocity is constant
B) its kinetic energy is constant
C) its acceleration is constant
D) it moves in a straight line
Correct Answer: B
Solution :
When force is perpendicular to velocity of particle, it is centripetal force whose magnitude is \[F=\frac{m{{v}^{2}}}{r}=\]constant ... (i) Also, kinetic energy \[K=\frac{1}{2}m{{v}^{2}}\] ...(ii) From Eqs. (i) and (ii), we get \[K=\frac{1}{2}m{{v}^{2}}=Fr=\]constant. Since, radius of circular path is always constant.
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