A) \[2\mu F\]
B) \[1\mu F\]
C) \[1.5\mu F\]
D) \[3\mu F\]
Correct Answer: B
Solution :
The given circuit consists of two \[1.5\mu F\] capacitors connected in parallel and this arrangement is connected to two\[3\mu F\] capacitors in series. Resultant capacitance C in parallel is \[C={{C}_{1}}+{{C}_{2}}\] \[=1.5\mu F+1.5\mu F=3\mu F\] \[\frac{1}{C}=\frac{1}{{{C}_{1}}}+\frac{1}{{{C}_{2}}}+\frac{1}{C}\] \[=\frac{1}{3}+\frac{1}{3}+\frac{1}{3}=\frac{3}{3}=1\] \[\Rightarrow \] \[C=1\,\mu F\]You need to login to perform this action.
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