A) \[\frac{4v}{A-4}\]
B) \[\frac{4v}{A+4}\]
C) \[\frac{v}{A-4}\]
D) \[\frac{v}{A+4}\]
Correct Answer: A
Solution :
From law of conservation of momentum, we have momentum before collision = momentum after collision The daughter nucleus has mass\[A-4\] \[\therefore \] \[{{m}_{\alpha }}{{v}_{\alpha }}+{{m}_{N}}{{v}_{N}}=0\] \[\Rightarrow \] \[4v+(A-4){{v}_{N}}=0\] \[{{v}_{N}}=\frac{-4v}{A-4}\]You need to login to perform this action.
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