A) \[\sqrt{2}v\]
B) v
C) \[\frac{v}{\sqrt{2}}\]
D) \[\frac{v}{2}\]
Correct Answer: A
Solution :
The orbital velocity\[({{v}_{o}})\]of a satellite at a height h above the surface of earth is \[{{v}_{o}}=\sqrt{\frac{G{{M}_{e}}}{{{R}_{e}}+h}}\] ?. (i) The escape velocity\[({{v}_{e}})\]is \[{{v}_{e}}=\sqrt{\frac{2G{{M}_{e}}}{{{R}_{e}}+h}}\] ?.. (ii) From Eqs. (i) and (ii), we get \[{{v}_{e}}=\sqrt{2}.{{v}_{o}}\] Given, \[{{v}_{o}}=v\] \[\therefore \] \[{{v}_{e}}=\sqrt{2}v\]You need to login to perform this action.
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