A) both\[\Delta H\]and\[\Delta S\]are +ve.
B) \[\Delta H\]is -ve and\[\Delta S\]is +ve
C) \[\Delta H\]is +ve and\[\Delta S\]is\[-ve\]
D) both\[\Delta H\]and\[\Delta S\]are\[-ve\]
Correct Answer: A
Solution :
In the process \[C{{O}_{2}}(s)\xrightarrow[{}]{{}}C{{O}_{2}}(g)\] the\[C{{O}_{2}}(s)\]changes into\[C{{O}_{2}}(g)\]hence, randomness increases and therefore, entropy also increases, i.e.,\[\Delta S=+\text{ }ve\]. This is an endothermic reaction, hence,\[\Delta H=+\text{ }ve\].
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