question_answer

Which of the -following complexes is tetrahedral and do not have any unpaired electrons?

A)  \[Ni{{[{{({{H}_{2}}O)}_{6}}]}^{2+}}\]      

B)  \[{{K}_{2}}[NiC{{l}_{4}}]\]

C)  \[{{K}_{2}}[Ni{{(CN)}_{4}}]\]     

D)  \[[Ni{{(CO)}_{4}}]\]

Correct Answer: D

Solution :

                 The oxidation number of Ni in\[[Ni{{(CO)}_{4}}]\]is zero. The hybridization in\[[Ni{{(CO)}_{4}}]\]is\[s{{p}^{3}}\]. Hence, the geometry of\[[Ni{{(CO)}_{4}}]\]is tetrahedral. It does not have any unpaired electrons.