A) 6
B) 5
C) 4
D) 7
Correct Answer: B
Solution :
The structure of isohexane is as: \[C{{H}_{3}}\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\] There are 5 monobromo derivatives of isohexane possible because there are five different positions where Br can be substituted.
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