A) A carboxyiic acid
B) An alcohol
C) A cyclic ester
D) An ether
Correct Answer: B
Solution :
Esters are reduced to alcohols with ethereal solution of\[LiAl{{H}_{4}}\]. \[\underset{Ethyl\text{ }acetate}{\mathop{C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}}}\,+4[H]\xrightarrow[ether]{LiAl{{H}_{4}}}\underset{ethyl\,alcohol}{\mathop{2{{C}_{2}}{{H}_{5}}OH}}\,\]You need to login to perform this action.
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