A) 600 g
B) 1000 g
C) 1250 g
D) 2000 g
Correct Answer: D
Solution :
\[{{t}_{1/2}}=10\text{ }days\] \[T=40\text{ }days\] \[n=\frac{T}{{{t}_{1/2}}}=\frac{40}{10}=4\] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}={{\left( \frac{1}{2} \right)}^{4}}\] \[\frac{125}{{{N}_{0}}}=\frac{1}{16}\] \[{{N}_{0}}=2000\,g\]You need to login to perform this action.
You will be redirected in
3 sec