A) \[R-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-R\]
B) \[R-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-{{O}^{-}}\]
C) \[R-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-Br\]
D) \[R-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-OR\]
Correct Answer: B
Solution :
\[C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-R\xrightarrow[O{{H}^{-}}]{B{{r}_{2}}}CHB{{r}_{3}}+\underset{(A)}{\mathop{RCO{{O}^{-}}}}\,\] This reaction is called as bromoform reaction. \[R-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}+3B{{r}_{2}}+4KOH\xrightarrow{\Delta }\underset{bromoform}{\mathop{CHB{{r}_{3}}}}\,\]\[+\text{ }RCOOK+3KBr+3{{H}_{2}}O\]
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