A) \[30{}^\circ \]
B) \[45{}^\circ \]
C) \[60{}^\circ \]
D) \[90{}^\circ \]
Correct Answer: A
Solution :
Let body projected with initial velocity u at an angle. with the horizontal. Then \[R=\frac{{{u}^{2}}\sin 2\theta }{g}\] \[{{H}_{m}}=\frac{{{u}^{2}}\sin \theta }{2g}\] Given, \[\frac{R}{{{H}_{m}}}=4\sqrt{3}\] \[\frac{2{{u}^{2}}\sin \theta \cos \theta }{g}=\frac{4\sqrt{3}{{u}^{2}}{{\sin }^{2}}\theta }{2g}\] \[\Rightarrow \] \[\cos \theta =\sqrt{3}\sin \theta \] \[\Rightarrow \] \[\cos \theta =\sqrt{3}\] \[\Rightarrow \] \[\theta ={{30}^{o}}\]You need to login to perform this action.
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