A) 0
B) 1
C) 7
D) 13
Correct Answer: D
Solution :
\[[O{{H}^{-}}]=0.1\] \[pOH=-log[O{{H}^{-}}]\] \[=-\text{ }log\text{ }[0.1]\] \[pOH=1\] \[pH+pOH=14\] \[pH=14-pOH\] \[=14-1=13\]You need to login to perform this action.
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