A) 1
B) 2
C) 3
D) 4
Correct Answer: C
Solution :
For Paschen series in hydrogen spectrum \[{{n}_{1}}=3,\text{ }{{\text{n}}_{2}}=4,\text{ }5,\text{ }6...\infty .\] \[\frac{1}{\lambda }=R\left( \frac{1}{{{3}^{2}}}-\frac{1}{n_{2}^{2}} \right)\]You need to login to perform this action.
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