A) \[1\text{ }m/{{s}^{2}}\]
B) \[4m/{{s}^{2}}\]
C) \[2\text{ }m/{{s}^{2}}\]
D) \[1.5\text{ }m/{{s}^{2}}\]
Correct Answer: B
Solution :
Rate of change of velocity gives acceleration. In this case the variation of v-t graph gives acceleration, which is maximum where the slope of curve is minimum. It is the region CD. \[\therefore \]Slope at CD = maximum acceleration \[=\frac{\Delta v}{\Delta t}=\frac{{{v}_{2}}-{{v}_{1}}}{{{t}_{2}}-{{t}_{1}}}\] \[=\frac{60-20}{40-30}=\frac{4}{1}\]
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