A) 1840 cm/s
B) 184.0 cm/s
C) 1840 m/s
D) 184.0 m/s
Correct Answer: C
Solution :
The root mean square velocity\[({{v}_{rms}})\]is by \[{{v}_{rms}}=\sqrt{\frac{3P}{\rho }}\] where P is pressure and p the density. Given, \[P=1.013\times {{10}^{3}}At.\] \[\rho =0.0000893\text{ }g/c{{m}^{3}}\] \[\rho =0.0000893\times 1000\text{ }kg/{{m}^{3}}\] \[\therefore \] \[{{v}_{rms}}=\sqrt{\frac{3\times 1.013\times {{10}^{5}}}{0.0000893\times 1000}}\] \[{{v}_{rms}}\approx 1840\,m/s\]
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