J & K CET Medical J & K - CET Medical Solved Paper-2001

  • question_answer
    A bucket full of hot water is kept in a room. It cools from \[75{}^\circ C\] to \[70{}^\circ C\] in f, minutes, from \[70{}^\circ C\] to \[65{}^\circ C\] in \[{{t}_{2}}\] minutes and from \[65{}^\circ C\] to \[60{}^\circ C\] int3 minutes. Then:

    A) \[{{t}_{1}}={{t}_{2}}={{t}_{3}}\]                

    B) \[{{t}_{1}}>{{t}_{2}}>{{t}_{3}}\]

    C)  \[{{t}_{1}}<{{t}_{2}}<{{t}_{3}}\]                

    D)  \[{{t}_{1}}<{{t}_{2}}>{{t}_{3}}\]

    Correct Answer: C

    Solution :

                     From Newtons law of cooling, when a hot body is cooled in air, the rate of loss of heat by is the body is proportional to the temperature difference between the body and the surrounding, Hence,       \[{{t}_{1}}<{{t}_{2}}<{{t}_{3}}\]


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