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J & K CET Medical J & K - CET Medical Solved Paper-2001

  • question_answer
    The wavelength\[{{\lambda }_{m}}\]of maximum intensity of emission of solar radiation is \[{{\lambda }_{m}}\] = 4753 \[\overset{0}{\mathop{A}}\,\] and from moon is \[{{\lambda }_{m}}\]= 14 \[\mu m.\] The surface tempe-rature of sun and moon are : (given \[b=2.898\times {{10}^{-3}}m-K\])

    A)  6097 K, 207 K                    

    B)  8097 K, 307 K

    C)  10,000 K. 400 K

    D)  3000 K, 100 K

    Correct Answer: A

    Solution :

                    From Weins displacement law, the relation between maximum wavelength\[({{\lambda }_{m}})\]and absolute temperature (T) is \[{{\lambda }_{m}}T=constant=b\] where   \[b=2.898\times {{10}^{-3}}m-K\] For sun,                 \[{{T}_{S}}=\frac{b}{{{\lambda }_{m}}}=\frac{2.883\times {{10}^{-3}}}{4753\times {{10}^{-10}}}=6097\,K\] For moon,                 \[{{T}_{m}}=\frac{b}{{{\lambda }_{m}}}=\frac{2.883\times {{10}^{-3}}}{14\times {{10}^{-6}}}=207\,K\]


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