J & K CET Medical J & K - CET Medical Solved Paper-2001

  • question_answer
    An electric bulb rated 100 W at 220 V is operating at 110 V. What is the power consumed?

    A)  50 W                                    

    B)  75 W

    C)  100 W                                  

    D)  25 W

    Correct Answer: D

    Solution :

                    From Joules law, the power consumed is \[P=\frac{{{V}^{2}}}{R}\] \[\Rightarrow \]               \[R=\frac{{{V}^{2}}}{P}\] \[\therefore \]  \[P=\frac{V{{}^{2}}}{R}=\frac{V{{}^{2}}}{{{V}^{2}}}\times P\] Given    \[V=110\,volt,\]                \[V=220\,volt,\] \[P=110\,\,W\] \[\therefore \]  \[P={{\left( \frac{110}{220} \right)}^{2}}\times 100=25\,W\]


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