A) 6 s
B) 4 s
C) \[\frac{\pi }{3}s\]
D) \[\frac{\pi }{2}s\]
Correct Answer: B
Solution :
The standard equation of a body executing SHM with amplitude a is \[y=a\sin \left( \frac{\pi }{2}t+\frac{\pi }{6} \right)\] ... (i) where\[\omega \]is angular velocity,\[\phi \]the phase. Given equation is \[y=10\sin \left( \frac{\pi }{2}t+\frac{\pi }{6} \right)\] ...(ii) Comparing Eqs. (i) and (ii), we get Also, \[\omega =\frac{2\pi }{T}\] \[\frac{2\pi }{T}=\frac{\pi }{2}\] \[\therefore \] \[T=4\,s\]You need to login to perform this action.
You will be redirected in
3 sec