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J & K CET Medical J & K - CET Medical Solved Paper-2001

  • question_answer
    The binding energy per nucleon for deuteron \[[_{1}^{2}H]\]and helium \[[_{2}^{4}He]\]are 1.1 MeV and 7 MeV. The energy released when two deuterons fuse to form a helium nucleus is :

    A)  32.4 MeV                           

    B)  23.6 MeV

    C)  16.2 MeV                           

    D)  11.8 MeV

    Correct Answer: B

    Solution :

                    When two deuterons fuse together energy is released \[_{1}{{H}^{2}}{{+}_{1}}{{H}^{2}}{{\xrightarrow{{}}}_{2}}H{{e}^{4}}+energy\] \[\therefore \] Energy released\[=(4\times 7-4\times 1.1)\]      = 23.6 MeV


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