A) \[{{n}_{1}}={{n}_{2}}\]
B) \[2{{n}_{1}}={{n}_{2}}\]
C) \[{{n}_{1}}=2{{n}_{2}}\]
D) \[3{{n}_{1}}=4{{n}_{2}}\]
Correct Answer: C
Solution :
Let\[l\]be the length of pipe, then fundamental frequency of open pipe is \[{{n}_{1}}=\frac{v}{2l}\] ?.. (i) where v is velocity of sound. For closed pipe \[{{n}_{2}}=\frac{v}{4l}=\frac{1}{2}\left( \frac{v}{2l} \right)\] ?. (ii) From Eqs. (i) and (ii), we get \[{{n}_{2}}=\frac{1}{2}{{n}_{1}}\] \[\Rightarrow \] \[{{n}_{1}}=2{{n}_{2}}\]You need to login to perform this action.
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