A) 32.4 MeV
B) 23.6 MeV
C) 16.2 MeV
D) 11.8 MeV
Correct Answer: B
Solution :
When two deuterons fuse together energy is released \[_{1}{{H}^{2}}{{+}_{1}}{{H}^{2}}{{\xrightarrow{{}}}_{2}}H{{e}^{4}}+energy\] \[\therefore \] Energy released\[=(4\times 7-4\times 1.1)\] = 23.6 MeVYou need to login to perform this action.
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