A) \[\frac{a}{2}\]
B) \[\frac{a}{2\sqrt{2}}\]
C) \[\frac{\sqrt{3}}{4}a\]
D) \[\frac{\sqrt{3}}{2}a\]
Correct Answer: B
Solution :
In a fee lattice, the lattice points are at corners plus one at the centre of each face of the cube. In fee lattice the spheres touch each other along a face diagonal. Since, atomic radius is the distance from the atomic nucleus to the outermost stable electron orbital in an atom that is at equilibrium.You need to login to perform this action.
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