A) 0.6
B) 60
C) 6
D) 600
Correct Answer: B
Solution :
Water contains\[C{{a}^{2+}}=\]0.06 g per kg = 0.06 g per 103 g Amount of\[C{{a}^{2+}}\]ion per 106 g water \[=\frac{0.06}{{{10}^{3}}}\times {{10}^{6}}\] \[=0.06\times {{10}^{3}}=60g\] Hence, the ppm level of\[C{{a}^{2+}}\]ions is 60.You need to login to perform this action.
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