A) The mixture has 25% R and 75% S
B) (b )The mixture has 20% R and 80% S
C) The mixture has 50% R and 50% S
D) The mixture has 75% R and 25% S
Correct Answer: A
Solution :
Specific rotation of (R) (-) 2-bromooctane is \[=-\,40\] Specific rotation of (S) (+) 2-bromooctane is \[=+40\] Let the mixture contains\[x\]%R and\[(100-x)\] % S form. \[\frac{x\times (-40)+(100-x)(+40)}{100}=20\] \[x=25\]and \[S=100-x=75\] Hence, the mixture has 25% R and 75% S.You need to login to perform this action.
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