A) 12 unit
B) 22 unit
C) 24 unit
D) 26 unit
Correct Answer: C
Solution :
Rate of change of velocity gives acceleration. Given, \[x={{t}^{3}}-2t\] Differentiating with respect to t, we get \[v=\frac{dx}{dt}=3{{t}^{2}}-2\] For acceleration \[v=\frac{dx}{dt}=\frac{{{d}^{2}}x}{d{{t}^{2}}}=6t\] Given, \[t=4\text{ }s\] \[\therefore \] \[a=6\times 4=24\text{ }m/{{s}^{2}}\]
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