J & K CET Medical J & K - CET Medical Solved Paper-2001

  • question_answer
    Light is an electromagnetic wave. Its speed in vacuum is given by the expression :

    A) \[\sqrt{{{\mu }_{0}}{{\varepsilon }_{0}}}\]                                           

    B) \[\sqrt{\frac{{{\mu }_{0}}}{{{\varepsilon }_{0}}}}\]

    C) \[\sqrt{\frac{{{\varepsilon }_{0}}}{{{\mu }_{0}}}}\]                                          

    D) \[\frac{1}{\sqrt{{{\mu }_{0}}{{\varepsilon }_{0}}}}\]

    Correct Answer: D

    Solution :

                    The speed of light is exactly 299, 792, 458 m/s (approximately\[3\times {{10}^{8}}\]m/s). The value of c defines the permittivity of free space\[({{\varepsilon }_{0}})\]in SI units as \[{{\varepsilon }_{0}}=\frac{{{10}^{7}}}{4\pi {{c}^{2}}}\] The permeability of free space\[({{\mu }_{0}})\]ls not dependent on c and is defined in SI units as                 \[{{\mu }_{0}}=4\pi \times {{10}^{-7}}\] These constants appear in Maxwells equations and are related as                 \[c=\frac{1}{\sqrt{{{\mu }_{0}}{{\varepsilon }_{0}}}}\]


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