A) \[30{}^\circ \]
B) \[60{}^\circ \]
C) \[45{}^\circ \]
D) \[90{}^\circ \]
Correct Answer: B
Solution :
For a prism of angle A and\[{{\delta }_{M}}\]the minimum angle of deviation, refractive index is given by \[\mu =\frac{\sin \left( \frac{A+{{\delta }_{m}}}{2} \right)}{\sin \frac{A}{2}}\] Given, \[\mu =\sqrt{3},\text{ }A={{60}^{o}}\] \[\therefore \] \[\sqrt{3}=\sin \left( \frac{\frac{{{60}^{o}}+{{\delta }_{m}}}{2}}{\sin \frac{{{60}^{o}}}{2}} \right)\] \[\Rightarrow \] \[\frac{{{60}^{o}}+{{\delta }_{m}}}{2}={{60}^{o}}\] \[\Rightarrow \] \[{{\delta }_{m}}={{60}^{o}}\]You need to login to perform this action.
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