question_answer

Which substance is acting as a reducing agent in the reaction? \[2MnO_{4}^{-}+16{{H}^{+}}+10F{{e}^{2+}}\xrightarrow{{}}2M{{n}^{2+}}\]\[+10F{{e}^{3+}}+8{{H}_{2}}O\]

A)  \[{{H}_{2}}O\]                                 

B)  \[{{H}^{+}}\]

C)  \[F{{e}^{2+}}\]                                

D)  \[MnO_{2}^{-}\]

Correct Answer: C

Solution :

                  Hence, in this reaction\[F{{e}^{2+}}\]acts as a reducing agent. It reduces\[MnO_{4}^{-}\]to\[M{{n}^{2+}}\].