A) propyl alcohol with KCN
B) butyl alcohol with KCN
C) butyl chloride with KCN
D) propyl chloride with KCN
Correct Answer: D
Solution :
Butanenitrile is prepared by heating propyl chloride with KCN. \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Cl+KCN\xrightarrow[{}]{\Delta }\underset{butanenitrile}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CN}}\,\] \[+KCl\]
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