A) 56 g
B) 2.5 g
C) 5 g
D) 28 g
Correct Answer: C
Solution :
\[\because \]Weight of 22.4 L of nitrogen at NTP = 28 g \[\therefore \]Weight of 4 L of N3 gas at\[NTP=\frac{28}{22.4}\times 4\] \[=5g\]You need to login to perform this action.
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