A) Butanol-2
B) Methanol
C) t-butanol
D) None of these
Correct Answer: A
Solution :
\[C{{H}_{3}}CHO\]and all other ketones containing \[COC{{H}_{3}}\]group give iodoform test. Butanol-2 on oxidation with\[Cr{{O}_{3}}\]gives ethylmethyl ketone, which gives iodoform test positive. \[\underset{butanol-2}{\mathop{C{{H}_{3}}C{{H}_{2}}\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{CH}}\,C{{H}_{3}}}}\,\] \[\xrightarrow[Cr{{O}_{3}}]{[O]}\underset{ethyl\text{ }methyl\text{ }ketone}{\mathop{C{{H}_{3}}C{{H}_{2}}-\underset{\begin{smallmatrix} |\,| \\ O \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}}}\,\] \[C{{H}_{3}}-C{{H}_{2}}-\underset{\begin{smallmatrix} |\,| \\ O \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\xrightarrow[NaOH]{{{I}_{2}}}\underset{\begin{smallmatrix} \,\,\,\,iodoform \\ (yellow\text{ }ppt.) \end{smallmatrix}}{\mathop{CH{{I}_{3}}}}\,\]
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