A) Acetone
B) Acetaldehyde
C) Propanaldehyde
D) Formaldehyde
Correct Answer: B
Solution :
Acetaldehyde undergoes aldol condensation to form aldol which gives\[C{{H}_{3}}CH=CHCHO\]on heating. \[\underset{acetaldehyde}{\mathop{C{{H}_{3}}CHO}}\,+H.\overset{\alpha }{\mathop{C{{H}_{2}}}}\,CHO\] \[\xrightarrow[NaOH]{dil.}\underset{aldol}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{2}}CHO}}\,\]\[\xrightarrow[-{{H}_{2}}O]{{{H}^{+}}\phi }\underset{crotonaldehyde}{\mathop{C{{H}_{3}}CH=CH-CHO}}\,\]
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