A) \[{{O}^{2-}}\]
B) \[{{S}^{2-}}\]
C) \[C{{l}^{-}}\]
D) \[B{{r}^{-}}\]
Correct Answer: A
Solution :
The size of ion decreases in a period from left to right and increases on moving from top to bottom in a group. Hence, the order of ionic radii is as- Anion: \[{{O}^{2-}}<C{{l}^{-}}<{{S}^{2-}}<B{{r}^{-}}\] Ionic radii: 142 pm 181 pm 184 pm 196 pm
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