A) \[CHC{{l}_{3}}\]
B) \[CC{{l}_{4}}\]
C) \[[Co{{(N{{H}_{3}})}_{3}}C{{l}_{3}}]\]
D) \[[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]Cl\]
Correct Answer: D
Solution :
\[[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]Cl\]compound gives a white Precipitate with silver nitrate solution because it has one lonizable chlorine\[[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]Cl{{[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]}^{+}}+C{{l}^{-}}\]
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