J & K CET Medical J & K - CET Medical Solved Paper-2002

  • question_answer
    Calculate\[{{t}_{1/2}}\]for a radioactive species having \[A=2.09\times {{10}^{-4}}mi{{n}^{-1}}\]:

    A)  23 days                               

    B)  230 days

    C)  0.23 days                           

    D)  2.3 days

    Correct Answer: D

    Solution :

                    \[{{t}_{1/2}}=\frac{0.693}{\lambda }\] \[=\frac{0.693}{2.09\times {{10}^{-4}}}\] \[=3315.7\,\min \] \[=\frac{3315.7}{60\times 24}=2.3\,days\]


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