A) \[8.8\times {{10}^{16}}m/{{s}^{2}}\]
B) \[8.8\times {{10}^{14}}m/{{s}^{2}}\]
C) \[8.8\text{ }m/{{s}^{2}}\]
D) \[8.8\times {{10}^{20}}m/{{s}^{2}}\]
Correct Answer: D
Solution :
The force experienced by an electron (e) in an electric field\[(E)\]is\[F=eE,\]and its acceleration is. \[a=\frac{F}{m}=\frac{eE}{m}\] Given, \[\frac{e}{m}=1.76\times {{10}^{11}}C-k{{g}^{-1}},\] \[E=50\times {{10}^{2}}V/m\] \[a=50\times {{10}^{2}}\times 1.76\times {{10}^{11}}\] \[\Rightarrow \] \[a=8.8\times {{10}^{14}}m/{{s}^{2}}\]
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