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J & K CET Medical J & K - CET Medical Solved Paper-2002

  • question_answer
    For the process\[{{H}_{2}}O(l){{H}_{2}}O(g)\]at\[{{100}^{o}}C,\] atm pressure:

    A)  \[\Delta H=T\Delta S\]                 

    B) \[\Delta H=0\]

    C)  \[\Delta H=\Delta E\]                   

    D) \[\Delta E=0\]

    Correct Answer: A

    Solution :

                    \[{{H}_{2}}O(l){{H}_{2}}O(g)\] Since, the process is in equilibrium. Hence, \[\Delta G=0.\] \[\because \]     \[\Delta G=\Delta H-T.\Delta S\]                 \[0=\Delta H-T.\Delta S\] \[\therefore \]  \[\Delta H=T.\Delta S\]


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