J & K CET Medical J & K - CET Medical Solved Paper-2002

  • question_answer
    A heater coil rated at (1000W-200V) is connected to 110 V line. What will be the power consumed?

    A)  200 W                                  

    B)  300 W

    C)  250 W                                  

    D)  350 W

    Correct Answer: B

    Solution :

                    From Joules law, the heat consumed is \[P=\frac{{{V}^{2}}}{R}\] where V is potential difference, R the resistance. \[\therefore \]  \[R=\frac{{{V}^{2}}}{P}\] Given, V = 200 volt,         P = 1000 W \[\therefore \]  \[R=\frac{{{(200)}^{2}}}{1000}=40\,\Omega \] When using 100 V line,                 \[P=\frac{{{V}^{2}}}{R}\]                 \[P=\frac{110\times 110}{40}=302\,W\] \[\therefore \]  \[P\approx 300W\]


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