A) zero
B) infinite
C) \[\frac{2{{\mu }_{0}}i(\pi +1)}{4\pi r}\]
D) \[\frac{2{{\mu }_{0}}i(\pi -1)}{4\pi r}\]
Correct Answer: D
Solution :
Field at the centre consists of two parts, one due to straight part of conductor and other due to coil of one turn. \[\therefore \] \[B={{B}_{2}}-{{B}_{1}}\] \[B=\frac{{{\mu }_{0}}}{4\pi }\frac{2\pi i}{r}-\frac{{{\mu }_{0}}}{4\pi }.\frac{2i}{r}\] \[B=\frac{2{{\mu }_{0}}i}{4\pi r}(\pi -1)\]
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